Question 954010
Solve algebraically for x: log5x-1 4=1/3
<pre>
If {{{log (5x - 1, 4) = 1/3}}}, then:
{{{log (5x - 1, 4) = 1/3}}} ---------- Logarithmic form
{{{highlight(highlight((5x - 1)^(1/3) = 4))}}} --------- Exponential form
{{{highlight(highlight((5x - 1)^((1/3) * 3) = 4^3))}}} ---- Cubing both sides
{{{highlight(highlight((5x - 1)^((1/cross(3)) * cross(3)) = 4^3))}}} 
5x – 1 = 64
5x = 64 + 1
5x = 65
x = {{{65/5}}}, or {{{highlight_green(13)}}}