Question 953656


if {{{a=(1/2)x+11}}} and {{{c=2x+1}}}, then 


{{{b^2=c^2-a^2}}}

{{{b^2=(2x+1)^2-((1/2)x+11)^2}}}

{{{b^2=(2x)^2+4x+1-(((1/2)x)^2+11x+121)}}}

{{{b^2=4x^2+4x+1-(1/4)x^2-11x-121)}}}

{{{b^2=(15/4)x^2-7x-120}}}

{{{b^2=(1/4)(15x^2-28x-480)}}}

{{{b=sqrt((1/4)(15x^2-28x-480))}}}

{{{b=(1/2)sqrt(15x^2-28x-480)}}}