Question 953636

{{{x= -(5/9)y-10/9}}}.......eq.1
{{{y=(2/3)x+31/3}}}......eq.2
---------------------------------substitute {{{x}}} from eq.1 in eq.2

{{{y=(2/3)(-(5/9)y-10/9)+31/3}}}......eq.2............solve for {{{y}}}


{{{y=-(10/27)y-20/27+31/3}}}..............both sides multiply by {{{27}}}

{{{27y=-10y-20+31*9}}}

{{{27y+10y=-20+279}}}

{{{37y=259}}}

{{{y=259/37}}}

{{{highlight(y=7)}}}

go to {{{x= -(5/9)y-10/9}}}.......eq.1 substitute {{{7}}} for {{{y}}} and solve for {{{x}}}

{{{x= -(5/9)7-10/9}}}

{{{x= -35/9-10/9}}}

{{{x= -45/9}}}

{{{highlight(x= -5)}}}