Question 953625
A natural number, when increased by 3, equals 70 times its reciprocal. Find the number
n=the number
{{{n+3=70(1/n)}}}
{{{n+3=70/n}}} Multiply each side by n.
{{{n^2+3n=70}}} Subtract 70 from each side.
{{{n^2+3n-70=0}}}
*[invoke quadratic "n", 1, 3, -70 ]
ANSWER: The number is 7.
CHECK:
7+3=70(1/7)
10=70/7
10=10