<PRE><B>Question 953564</B>
Two out of three mothers choose jam. If ten mothers are selected at random, what is the probability that at least one chooses jam. Looking for a binomial distribution. Please help.
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Binomial Problem with n = 10 and p(jam) = 2/3 [ p(not jam) = 1/3
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P(at least one jam) = 1 - P(none pick jam)
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= 1 - (1/3)^10
= 1 - 0.0000169
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=  0.99998
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Cheers,
Stan H.
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