Question 953557
What, this? R(x)=4/((x² -25)(x+2))


Trying to render, {{{R(x)=4/((x² -25)(x+2))}}}


Do you mean this?
{{{R(x)=4/((x^2-25)(x+2))}}}


Vertical asymptotes are x=5, x=-5, x=-2.
Factors of the denominator do not occur in the numerator, so no holes.


Finding your way:  {{{y=(x-r)/((x-c)(x-r))}}} is equivalent to {{{y=((x-r)/(x-r))(1/(x-c))}}}.