Question 953551
S=smaller; L=larger=S+2
{{{S^2-5L=26}}} Substitute for L
{{{S^2-5(S+2)=26}}} Subtract 26 from each side.
{{{S^2-5S-10-26=0}}}
{{{S^2-5S-36=0}}}
*[invoke quadratic "S", 1, -5, -36 ]
S=9 ANSWER 1: The smaller number is 9.
{{{L=S+2=11}}} ANSWER 2: The larger number is 11.
CHECK:
{{{S^2-5L=26}}}
{{{9^2-5(11)=26}}}
{{{81-55=26}}}
{{{26=26}}}