<PRE><B>Question 953524</B>
The sum of three integers is 17. The sum of the first and second integers exceeds the third by 71. The third integer is 63 less than the first. Find the three integers.
Let the integers be a, b, and c.
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Equations:
a + b + c = 17
a+b = c+71
c = a-63
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Rearrange:
a + b + c = 17
a + b - c = 71
a + 0 - c = 63
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Subtracting the top equation from the middle equation
you get -2c = 54
c = -27
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Substitute that into the bottom equation to get:
a +27 = 63
a = 36
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Substitute a and c into the top to solve for b::
36 + b - 27 = 17
9 + b = 17
b = 8
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Cheers,
Stan H.
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