Question 953539
The difference of two positive numbers is 2 and the sum of their squares is 74. Find the numbers
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x^2 + y^2 = 74
x - y = 2
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Solve for "x"::
x = y+2
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Substitute and solve for "y"::
(y+2)^2 + y^2 = 74
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y^2 + 4y + 4 + y^2 = 74
2y^2 + 4y + 4 = 74
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Modify::
y^2 + 2y - 35 = 0
(y+7)(y-5) = 0
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Positive solution:
y = 5
x = y+2 = 7
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Cheers,
Stan H.
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