Question 952640
Find QR.
{{{b^2=(0-5)^2+(-5-0)^2}}}
{{{b^2=25+25}}}
{{{b^2=50}}}
{{{b=5sqrt(2)}}}
Find ST.
{{{h^2=(-3-(-2))^2+(4-3)^2}}}
{{{h^2=1+1}}}
{{{h^2=2}}}
{{{h=sqrt(2)}}}
So then,
{{{A=(1/2)bh}}}
{{{A=(1/2)(5sqrt(2))(sqrt(2))}}}
{{{A=5}}}