Question 953422
Triangle ABC is such that its three angles ∠A, ∠B, ∠C are in the ration 3:4:5. What is the ratio of its three sides BC:CA:AB ?
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The angles are 45, 60 & 75 degs
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A/sin(A) = B/sin(B) = C/sin(C)
A:B:C = sin(45):sin(60):sin(75)
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The numerical ratios get messy.