Question 953313
n=first number; n+1=second number
((n)(n+1))-6=6(n+n+1)
n^2+n-6=6(2n+1)
n^2+n-6=12n+6 Subtract (12n+6) from each side.
n^2-11n-12=0*[invoke quadratic "n", 1, -11, -12 ]
ANSWER 1: The first positive integer is 12.
x+1=12+1=13  ANSWER 2: The second positive integer is 13.
CHECK:
(12*13)-6=6(12+13)
156-6=6(25)
150=150