Question 953189
The length of a rectangle is 4 cm more than 3 times its width. if the area of the rectangle is 15 sq cm, find the width whats the work 
<pre>Let width be W
Then length = 3W + 4
With area being 15 sq cm, we get: W(3W + 4) = 15
{{{3W^2 + 4W = 15}}}
{{{3W^2 + 4W - 15 = 0}}}
{{{3W^2 - 5W + 9W - 15 = 0}}}
{{{W(3W - 5) + 3(3W - 5) = 0}}}
3W - 5 = 0       OR       W + 3 = 0
3W = 5           OR       W = - 3 (ignore)
Width, or {{{highlight_green(W = 5/3)}}}, or {{{highlight_green(1&1/3)}}} cm