Question 953239
Line 1
{{{x}}}|	{{{y}}}
{{{3}}}|{{{	5}}}
{{{0}}}|{{{	4}}}

first find the equation of the line using given points:

{{{y=mx+b}}}......{{{0}}}|{{{	4}}}
{{{4=m*0+b}}}
{{{b=4}}}

{{{y=mx+b}}}......{{{3}}}|{{{	5}}}
{{{5=m*3+4}}}
{{{5-4=3m}}}
{{{m=1/3}}}

so, equation is:{{{y=(1/3)x+4}}}


Line 2
{{{x}}}|{{{	y}}}
{{{0}}}|{{{	4}}}
{{{6}}}|{{{	2}}}
 
 {{{y=mx+b}}}......{{{0}}}|{{{	4}}}
{{{4=m*0+b}}}
{{{b=4}}}

{{{y=mx+b}}}......{{{6}}}|{{{	2}}}
{{{6=m*2+4}}}
{{{6-4=2m}}}
{{{m=2/2}}}
{{{m=1}}}
so, equation is:{{{y=x+4}}}

{{{y=(1/3)x+4}}}
{{{y=x+4}}}
------------------if left sides equal, then right sides equal too

{{{(1/3)x+4=x+4}}}..........solve for {{{x}}}

{{{x/3=x+4-4}}}

{{{x-x/3=0}}}

{{{2x/3=0}}}

{{{highlight(x=0)}}}

then {{{y=0+4}}}=>{{{highlight(y=4)}}}

answer is:this system of equations have
 B.
exactly {{{1}}} solution

{{{ graph( 600, 600, -10, 10, -10, 10, x+4, (1/3)x+4) }}}