Question 81220
:
{{{x^2/((x^2-y^2))}}}
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{{{ x/((x+y))}}}
:
Remember, when you divide factions, invert the dividing fraction & multiply:
{{{x^2/((x^2-y^2))}}} *  {{{((x+y))/x}}}
:
(x^2-y^2) is the difference of squares, so factor:
{{{x^2/((x+y)(x-y)))}}} *  {{{((x+y))/x}}}
:
cancel (x+y)'s and x and you have:
{{{x/(x-y)}}}