Question 953086

{{{60x-2x^2}}} in the form {{{p-2(x-q)^2}}}

{{{-2x^2+60x}}}.....factor out {{{-2}}}

{{{-2(x^2-30x)}}} complete the square

{{{-2(x^2-30x+q^2)-(-2)q^2}}} .....since coefficient in front of {{{x^2}}} is {{{1}}} and in front of {{{x}}} is {{{30}}},we know that {{{2*1*q=30}}}; so, {{{q=15}}} 

{{{-2(x^2-30x+15^2)-(-2)15^2}}}

{{{-2(x-15)^2)+2*225}}}

{{{-2(x-15)^2+450}}}

or

{{{450-2(x-15)^2}}}