Question 952919


given:
X=girls 
Y=boys 
total {{{356}}} students

=> {{{X+Y=356}}}......eq.1...solve for {{{X}}}

{{{X=356-Y}}}......eq.1a


{{{34}}} more than {{{4}}} times the number of girls:{{{4X+34}}}
 is = to half the boys: {{{Y/2}}}

=> {{{4X+34=Y/2}}}......eq.2...substitute {{{X}}} from eq.1a


{{{4(356-Y)+34=Y/2}}}......solve for {{{Y}}}

{{{1424-4Y+34=Y/2}}}

{{{1458-4Y=0.5Y}}}

{{{1458=4.5Y}}}

{{{1458/4.5=Y}}}

{{{14580/45=Y}}}

{{{highlight(Y=324)}}}-> the number of boys


{{{X=356-Y}}}......eq.1a

{{{X=356-324}}}

{{{highlight(X=32)}}}-> the number of girls