Question 952798

{{{14y^2 -8}}}....first both terms multiply and divide by {{{7}}}


{{{(7*14y^2)/7 -(7*8)/7}}}

{{{(98y^2)/7 -56/7}}}....factor out {{{1/7}}}


{{{(1/7)(98y^2 -2*4*7)}}}....write {{{56}}} as {{{2*4*7}}}, then {{{7}}} as {{{sqrt(7)^2}}}


{{{(1/7)(2*49y^2 -2*4*sqrt(7)^2)}}}....factor out {{{2}}}


{{{(1/7)(2(49y^2 -4*sqrt(7)^2))}}}....write {{{4*sqrt(7)^2}}} as {{{(2*sqrt(7))^2}}}


{{{(2/7)((7y)^2 -(2sqrt(7))^2)}}}....factor the difference of the squares


{{{(2/7)((7y -2sqrt(7))(7y +2sqrt(7)))}}}