Question 952486
{{{ (a-2)*x^2=0 }}} 

{{{a<>2}}} ; result= double 0

you will get result= double 0 for any value of {{{a }}} you choose because  {{{(a-2)}}} is actually coefficient in front of variable {{{x}}}


example:

{{{ (a-2)*x^2=0 }}} if {{{a=-5}}}

{{{ (-5-2)*x^2=0 }}} 

{{{ -7x^2=0 }}} 

solution: result= double 0

{{{ (a-2)*x^2=0 }}} if {{{a=5}}}

{{{ (5-2)*x^2=0 }}} 

{{{ 3x^2=0 }}} 

solution: result= double 0

recall discriminant {{{b^2-4ac}}}:

the rule: if {{{b^2-4ac=0}}}, there will be 1 double 0, or one real root

in your case {{{ (a-2)*x^2=0 }}}

the value for {{{a}}} is actually {{{a-2}}},{{{b=0}}}, and {{{c=0}}}

{{{0^2-4(a-2)*0=0}}}

{{{0-4(a-2)*0=0}}}=> no matter what you put for {{{a}}} you will get

{{{0=0}}}