Question 952455

{{{12x+6y=120}}}....eq.1.....simplify;divide both sides by {{{3}}}
{{{4x+y=30}}}.......eq.2
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{{{4x+2y=40}}}....eq.1
{{{4x+y=30}}}.......eq.2
------------------------------subtract

{{{4x+2y-4x-y=40-30}}}

{{{2y-y=10}}}

{{{highlight(y=10)}}}

go to {{{4x+y=30}}}.......eq.2, substitute {{{10}}} for {{{y}}} and solve for {{{x}}}

{{{4x+10=30}}}

{{{4x=30-10}}}

{{{4x=20}}}

{{{x=20/4}}}

{{{highlight(x=5)}}}