Question 952422
a circle has its centre at the point (1,2) and passes through the point (0,3).find is equation 
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radius = the distance from (1,2) to (0,3)
r = sqrt(2)
{{{(x-1)^2 + (y-2)^2 = 2}}}
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and also that of the give me a solution of a circle whose centre is at the [point(4,3) and which cuts the first circle at right angles
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The 2nd circle is (x-3)^2 + (y-4)^2 = r^2
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I'll find r later today.