Question 952202

{{{(y + 3)^2-36 = 0}}}

{{{(y + 3)^2= 36}}}


{{{sqrt((y + 3)^2)= sqrt(36)}}}

{{{(y + 3)= sqrt(36)}}}

so, we have {{{(y + 3)= 6}}} and {{{(y + 3)= -6}}} 

solutions:

if {{{y + 3= 6}}}=> {{{y= 6-3}}}=>{{{y=3}}}
and
if {{{y + 3= -6}}}=> {{{y= -6-3}}}=>{{{y=-9}}}