Question 952113
If secθ = cscθ, and θ is not in Quadrant 1, determine the measure of θ in Radians or Degrees.
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csc = sec --> sine = cosine
{{{sin(x) = sqrt(1 - sin^2(x))}}}
sin^2 = 1 - sin^2
sin^2 = 1/2
{{{sin(x) = sqrt(2)/2}}}
--> x = 45 degs
sine and cosine are both + in Q1, and both negative in Q3
--> theta = 225 degrees = 5pi/4 radians