Question 952058
Think of this as one car standing still and
the other traveling at the sum of their speeds
Let {{{ s }}} = the speed of the slower car in km/hr
{{{ s + 10 }}} = the speed of the faster car in km/hr
Fro 2 PM to 2:30 PM = {{{ 1/2 }}} hr
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{{{ 60 = ( s + s + 10 )*(1/2) }}}
{{{ 120 = 2s + 10 }}}
{{{ 2s = 110 }}}
{{{ s = 55 }}}
{{{ s + 10 = 65 }}}
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Now change thinking back to both cars moving
Let {{{ d[1] }}} = distance in km slower car travels
Let {{{ d[2] }}} = distance in km faster car travels
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{{{ d[1] = 55*(1/2) }}}
{{{ d[1] = 27.5 }}}
and
{{{ d[2] = 65*(1/2) }}}
{{{ d[2] = 32.5 }}}
The slower car travels 27.5 km
The faster car travels 32.5 km
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check: 
{{{ 27.5 + 32.5 = 60 }}}
OK