Question 951962
A food company distributes its tomato soup in two cans of different sizes. For the larger can, the diameter has been increased by 10%, and the height remains the same.
By what percentage does the volume of the can increase from the smaller can to the larger can? Round your answer to the nearest percent.
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V = {{{pi*r^2*h}}}
If you increase the diameter by 10%, you also increase the radius by 10%
Assume the radius is 1, then if it is increased by 10% it will 1.1
Note that in the volume equation, the radius is squared therefore it will be
1.1^2 which equals 1.21; that is an increase in volume of 21%
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Let's prove that. let the radius = 10 and h = 20, find the volume
V = {{{pi*10^2*20}}} = 6283 cu/cm
Now increase the radius by 10%, then the radius = 11, h is still 20
V = {{{pi*11^2*20}}} = 7603 cu/cm
Find the increase in volume
7603 - 6283 = 1320 cu/cm increase
Find the percent increase
{{{1320/6283}}} * 100 = 21%
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