Question 951730
let {{{x}}} be the first integer, the next odd integer is {{{(x+2)}}}, the next one is {{{(x+4)}}}
The sum of three consecutive odd integers is {{{x+(x+2)+(x+4)}}}
the equation is
{{{x+(x+2)+(x+4)=69}}}
{{{x+x+2+x+4=69}}}
{{{3x=69-6}}}
{{{3x=63}}}
{{{x=63/3}}}
{{{x=21}}} is the first integer
{{{x+2=21+2=23}}}, {{{x+4=21+4=25}}}
Check the answer: {{{21+23+25=69}}} - correct
Answer: {{{21}}}, {{{23}}}, {{{25}}}