Question 81034
solve this problem {{{ 2^-1 + 2^0 + 2^1 }}}
Rules to use:
{{{highlight(a^(-m)=1/(a^m))}}}  
In other words, anything raised to a negative power can be written as 1 over that thing to the positive power.
{{{highlight(a^0=1)}}}
In other words, anything to the zero power is 1.
:
{{{(1/2^1)+1+2}}}
{{{1/2+1+2}}}
{{{1/2+3}}}
{{{1/2+3(2/2)}}}
{{{1/2+6/2}}}
{{{7/2}}}
Happy Calculating!!!! 3 1/2