Question 951644
{{{ 2x^2+5x-3=0 }}}
is the same as
{{{ 2x^2 + 6x - x - 3 = 0 }}}
Group factor here
2x(x + 3) - 1(x + 3) = 0
note that now you can factor out (x+3) and you have
(x + 3)(2x - 1) = 0
Which would give you the solutions that you have, not sure what you call this