Question 951576
solve for v, where v is a real number
^4√2v+2 +1=3 
Assume it's
{{{4sqrt(2v+2) + 1 = 3}}}
subtract 1 from both sides
{{{4sqrt(2v+2) = 2}}}
raise both sides to the 4th power
2v + 2 = 2^4
2v + 2 = 16
2v = 16 - 2
2v = 14
v = 14/2
v = 7
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Check this on your calc, enter (2(7)+2)^(1/4) + 1