Question 951600
Let {{{ m }}} = mule's burden
Let {{{ d }}} = donkey's burden
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given:
(1) {{{ m + 1 = 2*( d - 1 ) }}}
(2) {{{ m - 1  = d + 1 }}}
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(1) {{{ m +1  = 2d - 2 }}}
(1 {{{ 2d - m = 3 }}}
and
(2) {{{ m - 1  = d + 1 }}}
(2) {{{ -d + m = 2 }}}
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Add (1) and (2)
{{{ d = 5 }}}
and
(1) {{{ m + 1 = 2*( d - 1 ) }}}
(1) {{{ m + 1 = 2*( 5 - 1 ) }}}
(1) {{{ m = 2*4 - 1 }}}
(1) {{{ m = 7 }}}
The mule has 7 and the donkey has 5
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check:
Donkey gives mule 1, so donkey now
has 4 and mule has 8
8 is twice 4, OK
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Mule gives donkey 1, so mule has 6 and
donkey has 6
6 = 6, OK