Question 951419
The width of a rectangular painting is 5 inches shorter than the length.
 a. Write algebraic expressions to represent the width and the length of the painting.
Length = x
Width = x-5
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 b. Write an equation to model the area of the painting.
Area = length*width = x(x-5) = x^2-5x
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 c. Solve the quadratic equation.
You must solve it for some particular value of the Area.
Do you have a particular value?
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What do the x-intercepts mean in respect to the problem situation?
If Area = x(x-5), the x-intercepts are the value of
x and x-5 that make the Area = 0
That occurs when x = 0 or x = 5
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If x = 0, the length is zero ; so the Area = 0
If x = 5, the width (which is x-5) = zero ; so the Area = 0
Cheers,
Stan H.
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