<PRE><B>Question 951401</B>
A right triangle has a leg that measures 19 cm and a hypotenuse that measures 48 cm. Find the length of the missing leg to the nearest tenth.
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leg = sqrt[48^2-19^2] = sqrt(1943) = 44.08..
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2. In a 30-60-90 triangle, the hypotenuse measures 28 inches. What is the length of the short leg?
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If shortest is 1, the hypotenuse is 2, and the other leg is sqrt(3)
So, if hypo = 28, shortest = (1/2)28 = 14 inches
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3. A square has a diagonal that measures 50 inches.  Find the area of the square.
Area = side^2
If diagonal = 50, side = 50/sqrt(2)
Then area = (50/sqrt(2)^2 = 2500/2 = 1250 sq inches
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4. Which of the following is NOT a &quot;special&quot; right triangle? 
(1 point)
Ans: 20-70-90
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5. Find the perimeter of a right triangle that has a leg that measures 36 m and another leg that measures 15 m.
Hypotenuse = sqrt[36^2+15^2] = sqrt(1552
H = 39.4..
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Cheers,
Stan H.
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