Question 951161


if the ratio of two numbers  {{{R}}} and {{{T}}} is {{{7:2}}},then
 

{{{R/T=7/2}}}.....solve for {{{R}}}

{{{R=(7/2)T}}}....eq.1

and  if their sum is {{{261}}}, we have

{{{R+T=261}}}....eq.2....substitute {{{R}}} from eq.1

{{{(7/2)T+T=261}}}....solve for {{{T}}}

{{{7T/2+2T/2=261}}}

{{{9T/2=261}}}

{{{9T=261*2}}}

{{{9T=522}}}

{{{T=522/9}}}

{{{T=58}}}

go to eq.1 and plug in {{{T}}} and solve for {{{R}}}

{{{R=(7/2)58}}}....eq.1

{{{R=(7/cross(2))cross(58)29}}}

{{{R=7*29}}}

{{{R=203}}}