Question 951145
The four sides of a rhombus have equal measures. Let each side have length {{{x}}}.
Then the perimeter of the rhombus will be {{{P=4x}}}

given:
{{{d[1]=16}}}
{{{d[2]=30}}}

    diagonals of a rhombus are perpendicular and divide a rhombus into 4 right angle triangles 

each of right angle triangles has one leg equal to half of the length of one diagonal and the other leg is  half of the length of one diagonal, and hypothenuse is the side of the rhombus

so, {{{x^2=(d[1]/2)^2+(d[2]/2)^2}}}......plug in given values for diagonals


 {{{x^2=(16/2)^2+(30/2)^2}}}

{{{x^2=8^2+15^2}}}

{{{x^2=64+225}}}

{{{x^2=289}}}

{{{x=sqrt(289)}}}

{{{x=17}}}

Then the perimeter of the rhombus will be: 

{{{P=4x}}}

{{{P=4*17}}}

{{{P=68}}}