Question 951103
Domain is dictated by values that are not allowed. 
So look at the denominator first.
The denominator cannot equal zero so,
{{{sqrt(x)-4=0}}}
{{{sqrt(x)=4}}}
{{{x=16}}}
So {{{x=16}}} is excluded from the domain.
Also in the denominator, the argument for the square root must be non-negative so,
{{{x>=0}}}.
Now look at the numerator, it has the same square root restriction as the denominator.
So then putting it all together.
Domain:[{{{0}}},{{{16}}})U({{{16}}},{{{infinity}}})
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For the range, look at the limit values from the domain,
When {{{x=0}}}, {{{y=5/4}}}.
As x increases towards 16, y decreases towards {{{-infinity}}}.
When you approach 16 from the right, y increases towards {{{infinity}}}.
When x approaches infinity, y approaches 2. 
So then putting this all together,
Range : ({{{-infinity}}},{{{5/4}}})U({{{2}}},{{{infinity}}})
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{{{graph(300,300,-10,40,-25,25,(2sqrt(x)-5)/(sqrt(x)-4))}}}