Question 951087
Using log rules
 Loga = 0.3
 Logb = -0.5 

 Solve
 log(1000a^2)
= log(1000) + log(a^2)
= log(1000) + 2*log(a)
Base 10 is the default, and 1000 = 10^3
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= 3 + 2*0.3
= 3.6
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 log(4throot √(b/a))
{{{log(root(4,b/a))}}}
= (1/4)*log(b/a)
= (1/4)*[log(b) - log(a)]
= (1/4)*[-0.5 - 0.3] = (1/4)*(-0.8)
= -0.2
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 I need to evaluate while showing the use of log rules 
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 What I have is: log(1000)+log(a^2) 
 wouldn't log(1000) be the same as log[Base 10] 10 so would that count as the evaluation for that part? 
 then log(0.3^2) = log(0.09)
 therefore, the answer log[base 10]10 + log(0.09) 

 and log(4th root √(b/a)) would be log(b/a)^(1/4) and therefore log(-0.5)^(1/4) - log(0.3)^(1/4) 
 I feeel very unsure about these answers please help