Question 950991
It's a linear function so the graph is a straight line.
You can calculate the intercepts, the value where the line crosses the x and y axis.
X-intercept: Set {{{y=0}}} solve for {{{x}}}.
{{{0=3x+2}}}
{{{3x=-2}}}
{{{x=-2/3}}}
Y-intercept: Set {{{x=0}}} solve for {{{y}}}.
{{{y=3(0)+2}}}
{{{y=2}}}
So then (-2/3,0) and (0,2) are two points on the line.
Plot those then draw the line containing them.
(-2/3,0)
{{{drawing(300,300,-5,5,-5,5,grid(1),circle(-2/3,0,0.25))}}}
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(0,2)
{{{drawing(300,300,-5,5,-5,5,grid(1),circle(-2/3,0,0.25),circle(0,2,0.25))}}}
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Now draw the line {{{y=3x+2}}}
{{{drawing(300,300,-5,5,-5,5,grid(1),circle(-2/3,0,0.25),circle(0,2,0.25),graph(300,300,-5,5,-5,5,3x+2))}}}