Question 950930
If logb3=r and logb5=s, find the value of logb0.12 in terms of r and s.
***
{{{log(b,(0.12))=log(b,(12/100))=log(b,(3/25))=log(b,(3))-log(b,25))}}}
={{{log(b,(3))-2log(b,(5))=r-2s}}}