Question 950952
Carl, Diane, and Ed have $ 46.Carl has half as much as Diane, and Ed has $2 less than Diane. How
 much does each have?
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Equations:
c + d + e = 46
c = (1/2)d 
e = d-2
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Substitute for "c" and "e" and solve for "d"::
(1/2)d + d + d-2 = 46
(5/2)d = 48
d = 96/5
d = $19.20
c = $9.60
e = $17.20
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Cheers,
Stan H.
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