Question 950881
A rectangles perimeter: 

{{{P=2(L+W)}}}

if a rectangles perimeter is {{{P=65ft}}}, then we have

{{{65ft=2(L+W)}}}

if the length {{{L}}} is twice as long as the width {{{W}}}, then we have
 
{{{L=2W}}} ...substitute the length in equation above

{{{65ft=2(2W+W)}}}.....solve for {{{W}}}

{{{65ft/2=3W}}}

{{{32.5ft=3W}}}

{{{32.5ft/3=W}}}

{{{W=10.83333333333333ft}}}

{{{W=10.83ft}}}-the width

the length is:

{{{L=2W}}}

{{{L=21.66}}}