Question 950832

{{{root(3,40b^4) }}}......first write {{{40}}} as {{{8*5}}}, and {{{b^4}}} as {{{b^3*b}}}


{{{root(3,8*5b^3*b) }}}......write {{{8}}} as {{{2^3}}}

{{{root(3,2^3*5b^3*b) }}}.........write a root of product as {{{root(3,2^3)*root(3,5)root(3,b^3)*root(3,b) }}}......{{{root(3,2^3)=2}}} and {{{root(3,b^3)=b}}}

{{{2b*root(3,5)root(3,b )}}}

{{{2b*root(3,5b)}}}