Question 950791
I need to find the point that is equidistant from (2,6) (-3,1) (8,-6). 
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Another way to do it:
Label the points A(2,6) B(-3,1) C(8,-6)
Find the perpendicular bisectors of AB and of BC.
That will give you 2 equations in x & y.
Find the solution of those 2 equations.
That's the center of the circle, and is equidistant from A, B & C.