Question 950784
{{{A=B-6}}}
{{{A^2+B^2=20}}}
{{{(B-6)^2+B^2=20}}}
{{{B^2-12B+36+B^2=20}}}
{{{2B^2-12B+16=0}}}
{{{B^2-6B+8=0}}}
{{{(B-2)(B-4)=0}}}
Two solutions:
{{{B-2=0}}}
{{{B=2}}}
Then,
{{{A=2-6}}}
{{{A=-4}}}
and
{{{B-4=0}}}
{{{B=4}}}
Then,
{{{A=4-6}}}
{{{A=-2}}}