Question 950752
{{{ax+by=c}}}
When {{{y=0}}},{{{a(2)=c}}}
{{{a=c/2}}}
When {{{x=0}}},{{{b(6)=c}}}
{{{b=c/6}}}
So,
{{{(c/2)x+(c/6)y=c}}}
{{{x/2+y/6=1}}}
{{{y/6=-x/2+1}}}
{{{y=-3x+6}}}
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{{{drawing(300,300,-8,8,-8,8,grid(1),circle(0,6,0.42),circle(2,0,0.42),graph(300,300,-8,8,-8,8,-3x+6))}}}