Question 950596
<pre>
2x + y = 10
3x - {{{1/2}}}y = 11

Solve the first for y

y = 10 - 2x

Substitute (10 - 2x) for y in the second equation:


3x - {{{1/2}}}y = 11
3x - {{{1/2}}}(10 - 2x) = 11   <-- distribute the {{{1/2}}}
3x - 5 + x = 11
4x - 5 = 11
4x = 16
 x = 4

Substitute (4) for x in

y = 10 - 2x
y = 10 - 2(4)
y = 10 - 8
y = 2

Answer:  The two lines cross at (x,y) = (4,2)

{{{drawing(400,400,-5,5,-5,5,

graph(400,400,-5,5,-5,5), line(1,8,8,-6), line(2,-10,5,8),
locate(4.2,2.2,"(4,2)")  )}}} 

Edwin</pre>