Question 950552

Side1 {{{a= 2x^2+5}}}, 
Side2 {{{b= x^2+3x+4}}}, 
{{{P = 4x^2+12x+10}}}

find Side3 {{{c}}}

{{{P =a+b+c}}}.....solve for {{{c}}}

{{{c=P -(a+b)}}}.......plug in given values

{{{c=4x^2+12x+10 -(2x^2+5+x^2+3x+4)}}}

{{{c=4x^2+12x+10 -(3x^2+3x+9)}}}

{{{c=4x^2+12x+10 -3x^2-3x-9}}}

{{{c=x^2+9x+1}}}

so, Side3 is {{{x^2+9x+1}}}