Question 80816
Given a line containing the points (1,3), (2,4), (3,5) determine the slope-intercept form of the equation, give one additional point on this line and graph function.

Equation of line in slope-intercept form:
show your work:
Use the slope formula to find the slope of the line:
{{{m=(y[2]-y[1])/(x[2]-x[1])}}}  (x1,y1)=(1,3) (x2,y2)=(2,4)
{{{m=(4-3)/(2-1)}}}
{{{m=1/1}}}
{{{m=1}}}
Use the point slope formula to find the equation of the line:
{{{y-y[1]=m(x-x[1])}}} m=1 (x1,y1)=(1,3)
{{{y-3=1(x-1)}}}
{{{y-3=x-1}}}
{{{y-3+3=x-1+3}}}
{{{y=x+2}}} 
Check to make sure that the third point (3,5) is part of the line.
{{{5=(3)+2}}}
{{{5=5}}}
Ok, so all three points are colinear and the equation of their line is:
{{{highlight(y=x+2)}}}
Give one additional point in (x,y) form that would fall on this line:
Let x be anything, 0 hasn't been used yet.
{{{y=0+2}}}
{{{y=2}}}
Another point on the line would be: (0,2)

Graph the function:
Plot the points and connect them and you'll have the following line:
{{{graph(300,200,-10,10,-10,10,x+2)}}}
Happy Calculating!!!!