Question 950397
how do I go about solving these linear equations using substitution 
4x-y=5 --> y = 4x-5
4x+4y=-4
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Sub for y in the 2nd eqn
4x + 4(4x-5) = -4
x + 4x-5 = -1
5x = 4
x = 4/5
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y = -9/5