Question 950340
{{{ (3-j)(3-2j)/(2+3j^3) =(9-6j-3j+2j^2)/(2+3j(-1))}}}
{{{ (3-j)(3-2j)/(2+3j^3) =(9-9j-2)/(2-3j)}}}
{{{ (3-j)(3-2j)/(2+3j^3) =(7-9j)/(2-3j)}}}
{{{ (3-j)(3-2j)/(2+3j^3) =((7-9j)/(2-3j))((2+3j)/(2+3j))}}}
{{{ (3-j)(3-2j)/(2+3j^3) =(14+21j-18j-27j^2)/(4-6j+6j-9j^2)}}}
{{{ (3-j)(3-2j)/(2+3j^3) =(14+3j+27)/(4+9)}}}
{{{ (3-j)(3-2j)/(2+3j^3) =(41+3j)/(13)}}}