Question 950340
The expression, {{{ (3-j)(3-2j)/(2+3j^3) }}}, in simplest rectangular form is?

Struggling with this question, what steps do I take to solve this question? 
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There's nothing to solve, just rationalize.
j^3 = -j
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--> {{{ (3-j)*(3-2j)/(2-3j) }}}
= {{{ (9 -9j -2)/(2-3j) }}}
= {{{ (7 -9j)/(2-3j) }}}
Multiply NUM and DEN by the conjugate of the DEN
= {{{(7 -9j)*(2+3j)/((2-3j)*(2+3j))}}}
= {{{(14 +3j + 27)/13}}}
= {{{(41 +3j)/13}}}
or 41/13 + 3j/13